How do you write an equation in slope intercept form of a line passing through #(-4,-3)# and #(3,4)#?

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Answer 1 · 2017-03-04T22:34:44

#y = x+1#

By definition to find the slope of two given points we use the following formula:

#m = (y2-y1)/(x2-x1)#

So let's identify these values
#(-4,-3)# can be described as #(x1,y1)#

And,

#(3,4)# as #(x2,y2)#

Plugging in to the slope formula...
#m = (4-(-3))/(3-(-4))#
#m = 7/7# or #1#

Now that we have the slope we can find the equation by using the point-slope formula

#y-y1 = m(x-x1)#

(We have the slope so all we need is a point which can be any of the two that we were already given)

Let's use #(3,4)#

#y-4 = 1(x-3)#

Finally we can rewrite this in slope intercept form to get:

#y = x+1#