How do you normalize # (-2i- 3j + 2k) #?
1 Answer
Mar 5, 2017
Explanation:
In normalizing the vector we are finding a unit vector (magnitude/length of one) in the same direction as the given vector. This can be accomplished by dividing the given vector by its magnitude.
#u=v/(|v|)#
Given
#|v|=sqrt((v_x)^2+(v_y)^2+(v_z)^2)#
#|v|=sqrt((-2)^2+(-3)^2+(2)^2)#
#|v|=sqrt(4+9+4)#
#|v|=sqrt(17)#
We now have:
#u=(<-2,-3,2>)/sqrt(17)#
Hope that helps!
