How do you solve #(x - 4) ( 3x + 2) = 0#?

1 Answer
Shwetank Mauria
Mar 5, 2017

Solution is #x=0# or #x=-2/3#

Explanation:

From #(x-4)(3x+2)=0#

it is apparent that as product of #(x-4)# and #3x+2)# is #0#, we have

either #x-4=0# i.e. #x=4#

or #3x+2=0# i.e. #3x=-2# or #x=-2/3#

Hence solution is #x=0# or #x=-2/3#

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