Question

How do you solve `5x+2=6`?

Answer 1

`x=4/5`

Explanation:

Isolate 5x by subtracting 2 from both sides of the equation.

`5xcancel(+2)cancel(-2)=6-2`

`rArr5x=4`

To solve for x, divide both sides by 5

`(cancel(5) x)/cancel(5)=4/5`

`rArrx=4/5`

`color(blue)"As a check"`

Substitute this value into the left side and if equal to the right side then it is the solution.

`(cancel(5)^1xx4/cancel(5)^1)+2=4+2=6=" right side"`

`rArrx=4/5" is the solution"`