How do you solve #(x-5)^2=4#?
3 Answers
Explanation:
Explanation:
- Method 1-
- Method 2-
- Method 3-
Graphical Approach
Plot
Explanation:
To 'undo' the square on the left side.
#color(blue)"take the square root of both sides"#
#sqrt((x-5)^2)=+-sqrt4#
#rArrx-5=+-2larrcolor(red)" there are 2 solutions"#
#• x-5=+2#
#rArrx=2+5#
#rArrx=7to(color(red)(1))#
#• x-5=-2#
#rArrx=-2+5#
#rArrx=3to(color(red)(2))#
#color(blue)"As a check"# Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
#x=7to(7-5)^2=4=" right side"#
#x=3to(3-5)^2=4=" right side"#
#rArrx=3" or "x=7" are the solutions"#