How do you solve #\frac {p - 9} { 3} = 2#?

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Answer 1 · 2017-03-09T01:37:55

See the entire solution process below:

First, multiply each side of the equation by #color(red)(3)# to eliminate the fraction while keeping the equation balanced:

#color(red)(3) xx (p - 9)/3 = color(red)(3) xx 2#

#cancel(color(red)(3)) xx (p - 9)/color(red)(cancel(color(black)(3))) = 6#

#p - 9 = 6#

Now, add #color(red)(9)# to each side of the equation to solve for #p# while keeping the equation balanced:

#p - 9 + color(red)(9) = 6 + color(red)(9)#

#p - 0 = 15#

#p = 15#