How do you solve #9p + 4= 8p + 12#?

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Answer 1 · 2017-03-09T04:16:07

#p = 8#

#9p + 4 = 8p + 12#
#9p - 8p + 4 = 8p - 8p +12#
#p + 4 = 12#
#p +4 - 4 = 12 - 4#
#p = 8 #

Answer 2 · 2017-03-09T04:22:36

Isolate all values for the variable p using the inverse order of operations giving p = 8

The variable p is unknown something that is lost. When something is lost it is customary to work backwards to find what is lost.

PEMDAS backwards would be PESADM

The inverse order of operation can be remembered as if you find you have lost your cell phone in PE class you are a SAD Man

In this equation there are no parenthesis or exponents so the PE can be skipped.

The next step is Subtract and Add The opposite of + 4 is -4 so subtract 4 from both sides.

# 9p + 4 -4 = 8p + 12 -4# this results in

# 9p = 8p + 8 # Next subtract 8p from both sides

# 9p - 8p = 8p -8p + 8 # This results in

# 1p = 8 #