How do you use long division to divide $(4 x^{3} - 7 x^{2} - 11 x + 5) \div (4 x + 5)$ $(4x^3-7x^2-11x+5)div(4x+5)$ ?

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How do you use long division to divide $(4 x^{3} - 7 x^{2} - 11 x + 5) \div (4 x + 5)$ $(4x^3-7x^2-11x+5)div(4x+5)$ ?

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Answer 1 · 2017-03-09T13:31:17

The remainder is $= 0$ $=0$ and the quotient is $= x^{2} - 3 x + 1$ $=x^2-3x+1$

Explanation:

Let's do the long division

$a a a a$ $color(white)(aaaa)$ $4 x^{3} - 7 x^{2} - 11 x + 5$ $4x^3-7x^2-11x+5$ $a a a a$ $color(white)(aaaa)$ $∣$ $|$ $4 x + 5$ $4x+5$

$a a a a$ $color(white)(aaaa)$ $4 x^{3} + 5 x^{2}$ $4x^3+5x^2$ $a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $∣$ $|$ $x^{2} - 3 x + 1$ $color(red)(x^2-3x+1)$

$a a a a a a$ $color(white)(aaaaaa)$ $0 - 12 x^{2} - 11 x$ $0-12x^2-11x$

$a a a a a a a a$ $color(white)(aaaaaaaa)$ $- 12 x^{2} - 15 x$ $-12x^2-15x$

$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $- 0 + 4 x + 5$ $-0+4x+5$

$a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaa)$ $+ 4 x + 5$ $+4x+5$

$a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $+ 0 + 0$ $+0+0$

The remainder is $= 0$ $=0$ and the quotient is $= x^{2} - 3 x + 1$ $=x^2-3x+1$

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How do you use long division to divide $(4 x^{3} - 7 x^{2} - 11 x + 5) \div (4 x + 5)$ $(4x^3-7x^2-11x+5)div(4x+5)$ ?

1 Answer

Explanation:

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How do you use long division to divide (4x^3-7x^2-11x+5)div(4x+5)(4x3−7x2−11x+5)÷(4x+5)(4x^3-7x^2-11x+5)div(4x+5)?

1 Answer

Explanation:

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How do you use long division to divide $(4 x^{3} - 7 x^{2} - 11 x + 5) \div (4 x + 5)$ $(4x^3-7x^2-11x+5)div(4x+5)$ ?