How do you find the quotient of #(a^3-4a^2)div(a-4)#?

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Answer 1 · 2017-03-09T19:38:37

See the entire solution process below:

First, we write this expression as:

#(a^3 - 4a^2)/((a - 4))#

Next, factor the numerator as:

#(a^2(a - 4))/((a - 4))#

Now, cancel the common term in the numerator and denominator:

#(a^2color(red)(cancel(color(black)((a - 4)))))/(color(red)(cancel(color(black)((a - 4))))) ->#

#a^2#: Where #a - 4 != # or #a != 4#