How do you solve #3/8x+5/6=5/4x+2/3# by clearing the fractions?

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Answer 1 · 2017-03-12T00:37:12

Multiply both sides of the equation by a common factor such as #24.#

Multiply both sides of the equation by a common factor such as #24#:
#24*(3/8 x + 5/6) = 24*(5/4 x + 2/3)#

Simplify by dividing first, then multiplying:
#(24 * 3)/8 x + (24 * 5)/6 = (24 * 5)/4 x + (24 * 2)/3#

#3*3 x + 4*5 = 6*5 x + 8*2#

#9x + 20 = 30x + 16#

Add/Subtract Like terms:

#9x - 30x = 16 - 20#

#-21x = -4#

Divide by #-21# to isolate the variable #x#: #x = 4/21#