What is #K_a# of #"ZnCl"_2# ?
I know its small but what is the exact . Tell me the source too
I know its small but what is the exact . Tell me the source too
2 Answers
Explanation:
I was able to find a value for the acid dissociation constant of the
http://bilbo.chm.uri.edu/CHM112/tables/KaTable.htm
Of course, seeing how
You will have
#"ZnCl"_ (2(aq)) -> "Zn"_ ((aq))^(2+) + 2"Cl"_ ((aq))^(-)#
followed by
#"Zn"_ ((aq))^(2+) + 6"H"_ 2"O"_ ((l)) -> ["Zn"("H"_ 2"O")_ 6]_ ((aq))^(2+)#
and
#["Zn"("H"_ 2"O")_ 6]_ ((aq))^(2+) + "H"_ 2"O"_ ((l)) rightleftharpoons ["Zn"("H"_ 2"O")_ 5("OH")]_ ((aq))^(+) + "H"_ 3"O"_ ((aq))^(+)#
The Ka is nearly
Explanation:
http://www.webassign.net/labsgraceperiod/ucscgencheml1/lab_8/manual.pdf
In this website I checked that pH of 0.1M of ZnCl2 is 4.4
I tried to solve for Ka (
or
You can solve this by ICE table. Answer would be the same
The Ka is