How do you graph y=sin(x+pi/2)y=sin(x+π2)?

1 Answer
Mar 15, 2017

y=cos(x)y=cos(x)

Explanation:

sin(a+b) = sin(a)cos(b) + cos(a)sin(b)sin(a+b)=sin(a)cos(b)+cos(a)sin(b)

Hence:
sin(x+pi/2) = sin(x)cos(pi/2) + cos(x)sin(pi/2)sin(x+π2)=sin(x)cos(π2)+cos(x)sin(π2)

= sinx*0 + cosx*1 =cosx=sinx0+cosx1=cosx

:. the graph of y is the graph of cosx as below:

graph{cosx [-6.243, 6.24, -3.12, 3.123]}