How do you solve #2( t + 1) = - 8#?

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Answer 1 · 2017-03-17T00:29:38

#t=-5#

Steps:

Distribute the #2# to #(t+1)#

#2(t+1)=-8->2t+2=-8#

Subtract #2# to both sides

#2tcancel(+2-2)=-8-2 -> 2t= -10#

Divide each side by #2#

#cancel(2/2)t=-10/2#

#t=-5#