Question

Question #a3859

Answer 1

`T_2 = "846 K"` or `573^@"C"`

Explanation:

From the Ideal Gas Laws we know that `((PV)/T)_1 = ((PV)/T)_2`

At constant pressure this is just `((V)/T)_1 = ((V)/T)_2`
Inserting our given values into this equation with the correct temperature values we get:

`"0.300 L"/"423 K" = "0.600 L"/T_2` ; `T_2 = 0.600/(0.300/"423 K")`

`T_2 = "846 K"` or `573^@"C"`