How do you solve the system of equations #x+y+z=1#, #x+2y+z=2#, #x-y+z=-5# ?
1 Answer
Mar 18, 2017
This system has no solutions.
Explanation:
Given:
#{(x+y+z=1), (x+2y+z=2), (x-y+z=-5):}#
Adding the first and third equations, we get:
#2x+2z = -4#
Hence:
#x+z = -2" "...# (i)
Adding twice the third equation to the second equation, we get:
#3x+3z = -8#
Hence:
#x+z = -8/3" "...# (ii)
Equations (i) and (ii) are incompatible, since
So there is no solution to this system of equations.