Question #18b64

1 Answer
Mar 18, 2017

13.23

Explanation:

#tan x + 1/tan x = 2#
#tan^2 x + 1 = 2tan x#
#tan^2 x - 2tan x + 1 = 0#
Solve this quadratic equation for tan x.
Since a+ b + c = 0, use shortcut. There are 2 real roots:
tan x = 1 and #tan x = c/a = 1/2#.
a. tan x = 1 --> #x = pi/4#
#10x --> (10pi)/4 --> (5pi)/2 --> pi/2#
#tan 10x + cot 10x = tan (pi/2) + cot (pi/2) =# Inf. + 0 = Infinity (rejected)
b. #tan x = 1/2# --> #x = 26^@565#
#10x = 265^@65#
#tan 10x + cot 10x = tan (265.65) + cot (265.65) =#
#= 13.15 + 0.08 = 13.23#