Question

Question #9a7e4

Answer 1

The temperature is `=-131.6ºC`

Explanation:

We apply Charles' Law

`V_1/T_1=V_2/T_2`

`V_1=275mL`

`T_1=15+273=288K`

`V_2=135mL`

`T_2=V_2/V_1*T_1`

`=135/275*288`

`=141.4K`

`=141.4-273=-131.6ºC`