Question

Question #85c83

Answer 1

`( sin(​pi/2-​x)) /( ​cos(​pi-x))+( ​tan(​(3pi)/2-​x) )/ (​tan(​pi+​x))`

`=cosx /( -cosx)+cotx/ tanx`

`=-1+cot^2x`

`=cot^2x-1`