How do you find the derivative of 1 + tanx1+tanx? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x) 1 Answer Andrea S. Mar 21, 2017 As differentiation is linear: d/dx (1+tanx) = d/dx (1) + d/dx (tanx) = 0+1/cos^2x= 1/cos^2xddx(1+tanx)=ddx(1)+ddx(tanx)=0+1cos2x=1cos2x Answer link Related questions What is the derivative of y=cos(x)y=cos(x) ? What is the derivative of y=tan(x)y=tan(x) ? How do you find the 108th derivative of y=cos(x)y=cos(x) ? How do you find the derivative of y=cos(x)y=cos(x) from first principle? How do you find the derivative of y=cos(x^2)y=cos(x2) ? How do you find the derivative of y=e^x cos(x)y=excos(x) ? How do you find the derivative of y=x^cos(x)y=xcos(x)? How do you find the second derivative of y=cos(x^2)y=cos(x2) ? How do you find the 50th derivative of y=cos(x)y=cos(x) ? How do you find the derivative of y=cos(x^2)y=cos(x2) ? See all questions in Derivative Rules for y=cos(x) and y=tan(x) Impact of this question 17593 views around the world You can reuse this answer Creative Commons License