How do you solve #( x + 7)^2 = -11#?

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Answer 1 · 2017-03-22T16:14:58

#x = -7+isqrt 11 and -7-isqrt 11 #

#(x + 7)^2 = -11#

#(x + 7) = +-sqrt(-11)#

#(x + 7) =+- sqrt(-1 * 11)#

#(x + 7) = +-sqrt (-1) * sqrt 11#

#(x + 7) = +- i * sqrt 11#, where #i^2 = -1#

#x = -7+-isqrt 11#

#x = -7+isqrt 11 and -7-isqrt 11#