Question

How do you evaluate the integral `int sintheta/(2-costheta)`?

Answer 1

`int (sinthetad theta)/(2-cos theta) = ln (2-costheta) + C`

Explanation:

Substitute:

`x = 2-costheta`

`dx = sintheta d theta`

and we have:

`int (sinthetad theta)/(2-cos theta) = int dx/x= ln abs x+C = ln (2-costheta) + C`