How do you solve #3m+2=4#?

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Answer 1 · 2017-03-23T00:26:13

See the entire solution process below:

Step 1) subtract #color(red)(2)# from each side of the equation to isolate the #m# term while keeping the equation balanced:

#3m + 2 - color(red)(2) = 4 - color(red)(2)#

#3m + 0 = 2#

#3m = 2#

Step 2) Divide each side of the equation by #color(red)(3)# to solve for #m# while keeping the equation balanced:

#(3m)/color(red)(3) = 2/color(red)(3)#

#(color(red)(cancel(color(black)(3)))m)/cancel(color(red)(3)) = 2/3#

#m = 2/3#

Answer 2 · 2017-03-23T00:27:37

#2/3#

So first we want to get all terms with #m# by itself. In this case that means we are going to subtract 2 from both sides so it looks like this

#3m=2#

Now to get #m# all by itself, we will divide both sides by three so it looks like

#m=2/3#

Answer 3 · 2017-03-23T00:30:47

#m=2/3#

We want to isolate the variable so we began by subtracting #2# from both sides.

#3m+cancel(2-2)=4-2 -> 3m=2#

Now we can simply divide #3# on both sides

#cancel(3/3)m=2/3 -> m=2/3#

We can verify the solution by substituting #2/3# into the given equation like so:

#3*2/3+2=4#

#6/3+2=4#

#2+2=4#

#4=4# So we definitely correct!