How do you simplify #x^(3/7)/x^(1/3)#?

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Answer 1 · 2017-03-24T16:43:18

# x^(2/21)#

"If you are dividing and the bases are the same, subtract the indices."

Consider: #x^8/x^3 = x^(8-3) = x^5#

In the same way:

#(x^(3/7))/(x^(1/3)) = x^(3/7-1/3)#

Working with the fractions: find the LCD

# 3/7-1/3 = (9-7)/21 = 2/21#

#x^(3/7-1/3)= x^(2/21)#

Answer 2 · 2017-03-24T16:50:56

#x^(2/21)#

We know, a = #1/a^-1. So, 1/x^(1/3)= x^(-1/3)#

Thereby #x^(3/7) /x^(1/3) = x^(3/7). x^(-1/3) = x ^(3/7-1/3)#

#rArr x^[(9-7)/21] = x^(2/21)#