A container with a volume of #5 L# contains a gas with a temperature of #320^o K#. If the temperature of the gas changes to #280^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-03-25T07:59:18

The new volume is #=4.375L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=5L#

#T_1=320K#

#T_2=280K#

#V_2=T_2/T_1*V_1#

#=280/320*5#

#=4.375L#