Question

How do you evaluate `2+6(9-3^2)-2`?

Answer 1

The answer is `0`.

Explanation:

Use the order of operations `("PEMDAS")`.

`color(red)"P"` = parentheses
`color(blue)"E"` = exponents
`color(orange)"MD"` = multiplying and dividing
`color(violet)"AS"` = adding and subtracting

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`2+6 color(red)((9-3^2)) -2 color(white)"XXX"` Evaluate the `color(red)"P"`arentheses

within parentheses, we start over with `"PEMDAS"`

`(9-3^2) color(white)"XXXXXXX"` No `color(red)"P"`arentheses
`(9-color(blue)(3^2)) color(white)"XXxxxxxxx"` Evaluate the `color(blue)"E"`xponents
`(9-9) color(white)"xxXXxxxxxx"` No `color(orange)"M"`ultiplication or `color(orange)"D"`ivision
`(color(violet)(9-9))color(white)"xxXXxxxxxx"` Evaluate the `color(violet)"A"`ddition and `color(violet)"S"`ubtraction
`=(0)`

`2 + 6(0) - 2 color(white)"XXXXXX"` No `color(blue)"E"`xponents

`2 + color(orange)(6(0)) - 2 color(white)"XXXXXX"` Evaluate the `color(orange)"M"`ultiplication and `color(orange)"D"`ivision

`color(violet)(2+0-2) color(white)"XXXXXXX/"` Evaluate the `color(violet)"A"`ddition and `color(violet)"S"`ubtraction

`=0`

Final Answer