What is the Cartesian form of #(1,(pi )/4)#?

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Answer 1 · 2017-03-26T01:25:05

#(sqrt2/2, sqrt2/2)#

To find the Cartesian form of polar coordinates (i.e. the #x# and #y# coordinates), use the following formulas:

#x = r costheta#
#y = r sintheta#

In this case, #r = 1# and #theta = pi/4#.

So, just plug in these values to get your coordinates.

#x = 1 * cos(pi/4) = sqrt2/2#
#y = 1 * sin(pi/4) = sqrt2/2#

Therefore, the Cartesian form of #(1, pi/4)# is #(sqrt2/2, sqrt2/2)#.

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