How do you divide $(3 x^{2} + 11 x + 1) \div (x - 3)$ $(3x^2+11x+1)div(x-3)$ using long division?

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How do you divide $(3 x^{2} + 11 x + 1) \div (x - 3)$ $(3x^2+11x+1)div(x-3)$ using long division?

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Answer 1 · 2017-03-27T15:35:42

quotient $= 3 x + 20$ $color(blue)(=3x+20$ and remainder $= 60$ $color(blue)(=60$

Explanation:

$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $3 x + 20$ $color(blue)(3x+20$
$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $- - - - - -$ $------$
$a a a a x - 3$ $color(white)(aaaa)x-3$ $∣$ $|$ $3 x^{2} + 11 x + 1$ $3x^2+11x+1$ $a a a a$ $color(white) (aaaa)$ $∣$ $∣$ $color(blue)$
$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $3 x^{2} - 9 x$ $3x^2-9x$ $color(white)$
$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $- - - -$ $----$
$a a a a a a a a a a a$ $color(white)(aaaaaaaaaaa)$ $0 + 20 x + 1$ $0+20x+1$
$a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaa)$ $20 x - 60$ $20x-60$
$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $- - -$ $---$
$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $0 + 60$ $0+60$

remainder is $= 60$ $color(blue)(=60$ and the quotient is $= 3 x + 20$ $color(blue)(=3x+20$

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How do you divide $(3 x^{2} + 11 x + 1) \div (x - 3)$ $(3x^2+11x+1)div(x-3)$ using long division?

1 Answer

Explanation:

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How do you divide (3x2+11x+1)÷(x−3)(3x^2+11x+1)div(x-3) using long division?

1 Answer

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How do you divide $(3 x^{2} + 11 x + 1) \div (x - 3)$ $(3x^2+11x+1)div(x-3)$ using long division?