What is the polar form of #( 12,144 )#?

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Answer 1 · 2017-03-27T22:02:19

#(144.499,1.488)#

To find #r^2#, use Pythagorean theorem:

#12^2+144^2=r^2#

#r=144.499#

To find he angle, use tangent:

#tan theta = 144/12#

#theta= 1.488#

Rewrite this in the form #(r,theta)#

#(144.499,1.488)#