Question #13f21

Question

1917 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-28T07:43:52

The length of the wire is #=0.2m#

We apply the equation

#f=1/(2L)sqrt(T/mu)#

Frequency is #=f Hz#

Length of wire is #=L m#

Tension is #=T N#

Lineal density is #mu kgm^-1#

Initial conditions

#256=1/(2*0.8)sqrt(T/mu)#

#sqrt(t/mu)=256*2*0.8#

New frequency is

#f_1=1024=1/(2L_1)*256*2*0.8#

#L_1=256/1024*2*0.8/2#

#L_1=0.2m#