How do you find the domain of #y =-sqrt(x+1 )-6#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Douglas K. Mar 28, 2017 Assuming that y is restricted to a real number, (#y in RR#), then the argument for the square root must be greater than or equal to 0: Explanation: #x + 1 >=0# #x >=-1 larr# This is the domain Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1309 views around the world You can reuse this answer Creative Commons License