The gas inside of a container exerts #"36 Pa"# of pressure and is at a temperature of #"75 K"#. If the temperature of the gas changes to #"125 K"# with no change in the container's volume, what is the new pressure of the gas?

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Answer 1 · 2017-03-29T05:58:22

The new pressure is #=60Pa#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#

Pressure, #P_1=36Pa#

Temperature, #T_1=75K#

Temperature, #T_2=125K#

Pressure, #P_2=T_2/T_1*P_1#

#=125/75*36=60Pa#