Question #3719b

1 Answer
NickTheTurtle
Mar 29, 2017

I am interpreting your question as #2^(2/3)*6^(1/3)#. The answer is #2*3^(1/3)=2root(3)(3)#.

Explanation:

Notice that #(ab)^c=a^c*b^c#. We can rewrite #6^(1/3)#as #2^(1/3)*3^(1/3)#.

The question thus becomes #2^(2/3)*2^(1/3)*3^(1/3)#. However, #a^b*a^c=a^(b+c)#. We can rewrite #2^(2/3)*2^(1/3)# as #2^(2/3+1/3)=2^1=2#.

The final answer is #2*3^(1/3)#. We can also write this using radical form: #2root(3)(3)#

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