Question

Question #74b68

Answer 1

Either factor or use quadratic formula. In this case, the zeros are `3` and `-2`.

Explanation:

Solving a quadratic function means to find the roots/zeros (same meaning, different word).

There are two ways to accomplish this:

1. Factor the equation (from standard to factored form).
2. Use the quadratic formula (in standard form).

Let's try factoring. Factoring is the fast and easier method of solving a quadratic function.

So first, let's find a common factor. In this case, I noticed that `8` is common in all terms. So let's use that as our greatest common factor.

`f(x)=-8x^2+8x+48`

`f(x)=-8(x^2-x-6)`

I took out the negative sign to make factoring much easier.

Now, we have a simple trinomial. So let's factor it normally: what two numbers added equals `b` and multiplied, equals `ac`? In this case, it is `-3` and `2`.

`f(x)=-8(x-3)(x+2)`

And those are the zeros: `3` and `-2`.

If factoring did not work, we would have to use the quadratic formula and plug in the numbers from standard form.

Hope this helps :)