Question

How do you find the quotient of `(2x+8)/(x+3)div(x+4)/(x^2+6x+9)`?

Answer 1

`2 x + 6`

Explanation:

`(2 x + 8)/(x + 3) -: (x + 4)/(x^2 + 6 x + 9)`

change the sign `-:` to * ( multiplication) and change the position of `(x + 4)/(x^2 + 6 x + 9)` to `(x^2 + 6 x + 9)/ (x + 4)`

`= (2 x + 8)/(x + 3) * (x^2 + 6 x + 9)/ (x + 4)`

`= (2(cancel( x + 4)))/cancel((x + 3)) * ((x + 3)cancel((x + 3)))/ cancel((x + 4))`

`= 2(x + 3) = 2 x + 6`