Question

Question #9ebb1

Answer 1

`1Al(OH)_2+3HC_2H_3O_2 rarr 1Al(C_2H_3O_2)_3 +3H_2O`

Explanation:

Here's a suggestion:

Treat the acetate ion (the #C_2H_3O_2 in the formulas) as a single unit, because it does not change in the process. This will greatly simplify the task, as your equation will now look like this:

`Al(OH)_3 + HA rarr AlA_3 + H_2O`

where I substitute `A` in place of `C_2H_3O_2`

Place a "1" in front of `Al(OH)_3` and also in front of the `AlA_3`
Now, the `Al` atoms balance.

Place a "3" in front of `HA` because you must balance the three `A` (acetate) that now appear on the right side.

Finally, you have a total of three oxygen atoms and six hydrogen atoms on the left side - just enough for three water molecules on the right.