Question

How do you find the x and y intercept of `-2x+5y=20`?

Answer 1

See the entire solution process below:

Explanation:

Y-Intercept)

To find the y-intercept, set `x` equal to `0` and solve for `y`:

`-2x + 5y = 20` becomes:

`(-2 * 0) + 5y = 20`

`0 + 5y = 20`

`5y = 20`

`(5y)/color(red)(5) = 20/color(red)(5)`

`(color(red)(cancel(color(black)(5)))y)/cancel(color(red)(5)) = 4`

`y = 4`

The y-intercept is `4` or `(0, 4)`

X-Intercept)

To find the x-intercept, set `y` equal to `0` and solve for `x`:

`-2x + 5y = 20` becomes:

`-2x + (5 * 0) = 20`

`-2x + 0 = 20`

`-2x = 20`

`(-2x)/color(red)(-2) = 20/color(red)(-2)`

`(color(red)(cancel(color(black)(-2)))x)/cancel(color(red)(-2)) = -10`

`x = -10`

The x-intercept is `-10` or `(-10, 0)`