How do you write # (2x^2 – 11x) + (4x^2 – 4) # in standard form?

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Answer 1 · 2017-03-31T22:19:19

See the entire solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#2x^2 - 11x + 4x^2 - 4#

Next, group like terms in order of the power of the exponent of the #x# terms:

#2x^2 + 4x^2 - 11x - 4#

Now, combine like terms:

#(2 + 4)x^2 - 11x - 4#

#6x^2 - 11x - 4#