Question

How much work does it take to raise a `23 kg` weight `11 m`?

Answer 1

`W = 2479.4 J`

Explanation:

`"Work"` is formulated by:

`W = F*d*cos(theta)`

Where
`F="force"`
`d="displacement", and`
`(theta)="angle between the force and the displacement vector"`

In this scenario, a `"force"` is being applied to an object to cause it to be `displaced`. Therefore, work was done on the object.

Since the angle between the force (the mass times acceleration due to gravity) and the displacement (11 meters) is `0^@`, and the cosine of `0^@` is 1, we can calculate the work done to raise the object as follows,

`W = F*d*cos(theta)`
`W = (m*g) *d*cos(theta)`
`W = (23kg * 9.8 m/s^2) * 11m*cos(0^@)`
`W = 2479.4 J`

Answer: 2479.4 J