How do you find the domain and range of #f(x)=sqrt(8-x)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Konstantinos Michailidis Apr 2, 2017 The domain is #8-x>=0# or #8>=x# hence #D_f=(-oo,8]# and the range is #f(x)=sqrt(8-x)>=0# or #R_f=[0,+oo)# Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1196 views around the world You can reuse this answer Creative Commons License