How do you find the equation, in slope-intercept form, of the line that passes through the points (-3,3) and (-4,2)?

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Answer 1 · 2017-04-05T03:19:33

#y=x+6#

Slope-intercept or #y=mx+b#

Use the points #P1(-3,3) and P2(-4,2)# to calculate the slope.

#m=(Y2-Y2)/(X2-X1)#

#m=(2-3)/(-4--3)#

#m=1#

Sub #m# into the slope-intercept equation,

#y=x+b#

To solve for #b,# use either #P1 or P2# (im going to use #P1#)

#3=-3+b#

#b=6#

Therefore the equation that passes through #P1 and P2# is #y=x+6#

graph{x+6 [-10, 10, -5, 5]}