How do you find the x and y intercept of #3x+2y=6#?

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Answer 1 · 2017-04-05T12:59:59

#y_("intercept")=3 ->(x,y)=(0,3)#

#x_("intercept")=2->(x,y)=(2,0)#

Subtract #3x# from both sides giving:

#2y=-3x+6#

Divide each side by 2

#y=-3/2 x+3#
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The y-intercept is at #x=0# giving:

#y=-3/2(0)+3#

#y_("intercept")=3 ->(x,y)=(0,3)#
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The x-intercept is at #y=0# giving:

#0=-3/2x+3#

#3/2x=3#

#x=2/3xx3 =2#

#x_("intercept")=2->(x,y)=(2,0)#