Question #7171a

1 Answer
Apr 7, 2017

(x^2y^2)/(x^2+y^2)

Explanation:

the denominator y^-2+x^-2 can be written as

1/y^2+1/x^2

=(x^2+y^2)/(x^2y^2)

Now;
1/(y^-2+x^-2) = (y^-2+x^-2)^-1

=((x^2+y^2)/(x^2y^2))^-1

=color(red)((x^2y^2)/(x^2+y^2))