Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

What is the area enclosed by #r=-3sin(2theta-(2pi)/4) -theta# between #theta in [pi/8,(3pi)/4]#?

1 Answer

Frederico Guizini S.

Apr 9, 2017

See the answer below:
enter image source here

Related questions

How do you find the area of the region bounded by the polar curve #r=3cos(theta)# ?
How do you find the area of the region bounded by the polar curve #r=3(1+cos(theta))# ?
How do you find the area of the region bounded by the polar curve #r=2-sin(theta)# ?
How do you find the area of the region bounded by the polar curve #r^2=4cos(2theta)# ?
How do you find the area of the region bounded by the polar curve #r=2+cos(2theta)# ?
How do you find the area of the region bounded by the polar curves #r=sqrt(3)cos(theta)# and...
How do you find the area of the region bounded by the polar curves #r=1+cos(theta)# and...
How do you find the area of the region bounded by the polar curves #r=cos(2theta)# and #r=sin(2theta)# ?
How do you find the area of the region bounded by the polar curves #r^2=cos(2theta)# and...
How do you find the area of the region bounded by the polar curves #r=3+2cos(theta)# and...

See all questions in Calculating Polar Areas

Impact of this question

1754 views around the world

You can reuse this answer
Creative Commons License