Question

How do you find the domain of `f(x)=sqrt(2x^2-5x+2)`?

Answer 1

`D=R` without `{1/2, 2}`

Explanation:

`2x^2-5x+2>=0`

`b^2-4ac=25-4*2*2=9`
`sqrt(9)=3`

`x_1=(5-3)/4=1/2`
`x_2=(5+3)/4=2`

`D=R` without `{1/2, 2}`