What is the norm or #< 8 ,-4 , 9 >#?

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Answer 1 · 2017-04-11T06:12:21

The norm is #=12.69#

The norm of a vector #veca= <p,q,r># is

#||veca||=sqrt(p^2+q^2+r^2)#

So, we have

#||<8,-4,9>||=sqrt(8^2+(-4)^2+9^2)#

#=sqrt(64+16+81)#

#=sqrt(161)#

#=12.69#