How do you find the slope of the line (-3,3) and (0,-3)?

Question

1507 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-11T10:01:18

$= - 2$ $=-2$

the slope of a line with co-ordinates

$(x_{1}, y_{1}), (x_{2}, y_{2})$ $(x_1,y_1), (x_2,y_2)$

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1$

for

$(- 3, 3), (0, - 3)$ $(-3,3), (0,-3)$

$m = \frac{- 3 - 3}{0 - - 3}$ $m=(-3 -3)/(0- -3)$

$m = \frac{- 3 - 3}{3}$ $m=(-3-3)/(3)$

$m = \frac{- 6}{3} = - 2$ $m=(-6)/3=-2$