Question

A cyclist goes on a 40 km round trip. The cyclists speed going north is `4` kmph more than coming back south. What is the cyclist's speed heading north and south?

Answer 1

The bicyclist heading north is moving at `18` km/h and the bicyclist heading south is moving at `14` km/h.

Explanation:

An hour and a quarter has passed and they are `40` kms apart. By the formula `s= d/t -> d = s(t)`, letting `x` be the speed of the south-bound cyclist, we have:

`5/4(x + 4) + 5/4(x) = 40`

`5/4x + 5 + 5/4x = 40`

`5/2x = 35`

`x = (35)/(5/2)`

`x = 14`

This means that the cyclist heading south travels at `14` km/h, and so the cyclist heading north was traveling at `18` km/h.

Hopefully this helps!