Question #58fdd

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Answer 1 · 2017-04-13T19:06:24

# (+-sqrt3/2,0).#

#x^2=1-4y^2 rArr x^2+4y^2=1, or, x^2+y^2/(1/4)=1#

Comparing with the Standard Eqn. of Ellipse, i.e.,

#x^2/a^2+t^2/b^2=1,# we have, #a^2=1, b^2=1/4, so, a >b.#

Knowing that the Eccentricity #e# is given by,

#b^2=a^2(1-e^2),# we get, #1/4=1(1-e^2)#

#:. e=sqrt3/2.#

Therefore, the Focii are, #(+-ae,0)=(+-sqrt3/2,0).#

Enjoy Maths.!