How do you simplify #x^6/ x^2#?

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Answer 1 · 2017-04-14T08:43:14

#x^4#

Let's write the equation in this form #(x^4*x^2)/(x^2)#

Now numerator's #(x^2)# will cancel the one in the denominator:
#(x^4\cdot\cancel(x^2))/(\cancel(x^2))=x^4#

Yielding #x^4#.

Answer 2 · 2017-04-14T09:24:33

(the previous answer also works)!
#x^4#

#x^a/x^b=x^(a-b)#

here you have #a=6# and #b=2#
#\thereforex^6/x^2\rArrx^(6-2)=x^4#