Question

Question #b7424

Answer 1

C)

Explanation:

Let acceleration of the wagons be `= a`

Given the engine exerts a force `=16000 N` on `10` wagons.

Mass of ten wagons `m = "Mass of one wagon" xx "Number of wagons"`
`=>m = 1000 xx 10`
`=>m = 10000 kg`

Applying Newton’s second law of motion we get
`F= ma`
`=>a=F/m = 16000/10000 = 1.6 ms^-2`

Again applying Newton's second law of motion to fine the force applied by 9th wagon on 10th wagon `="mass of tenth wagon"xx"acceleration of tenth wagon"`
`=1000xx1.6=1600N`